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30x^2-62x-48=0
a = 30; b = -62; c = -48;
Δ = b2-4ac
Δ = -622-4·30·(-48)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-62)-98}{2*30}=\frac{-36}{60} =-3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-62)+98}{2*30}=\frac{160}{60} =2+2/3 $
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